and the tangential component is = 2. dr d. θ 2. d. θ. a. θ. (6.5.16) dt. 2. dt + r. dt. The firs term in the tangential component of the acceleration, 2(dr / dt)(d. θ / dt) has a special name, the . coriolis acceleration, = 2. dr d. θ. a. cor. (6.5.17) dt dt. Example 6.4 Spiral Motion ⎞ ⎠ ⎛ ⎝ A particle moves outward along a spiral starting from the origin at . t = 0 . Its trajectory is

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    Find the tangential and normal components of the acceleration vector at the given point. r (t) = lnt i + (t^2+3t)j + 4*t^ (1/2)k (0, 4, 4)

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    Join the ladybug in an exploration of rotational motion. Rotate the merry-go-round to change its angle, or choose a constant angular velocity or angular acceleration. Explore how circular motion relates to the bug's x,y position, velocity, and acceleration using vectors or graphs.

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